a positive of +50 charge is placed in an electric field 50,000 n/c directed in the upward direction. what mass should the charge

a positive of +50 charge is placed in an electric field 50,000 n/c directed in the upward direction. what mass should the charge have be remain suspended in air​

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  1. Given info : A positive of +50μC charge is placed in an electric field 50,000 N/C directed in the upward direction.

    To find : What mass should the charge have be remain suspended in air ?

    solution : electrostatic force acts upwards and weight of body acts downwards. it means, weight of body balances the electrostatic force.

    so weight of body = electrostatic force

    ⇒mg = qE

    here g = 10 m/s² [ acceleration due to gravity] , q = 50μC and E = 50,000 N/C

    ∴ m × 10 = 50 × 10¯⁶ × 50000

    ⇒m = 25 × 10¯² kg = 250 g

    Therefore the weight of body is 250g

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