A positive number is 5 times to another number. if 21 is added to both the numbers,then one of the new numbers becomes twice the another new number. find the two numbers. Please folow me and mark my all answers as it brainlist.
Given,A positive number is 5 times to another number. if 21 is added to both the numbers,then one of the new numbers becomes twice the another new number.
Tofind,Required two numbers
Solution:
According to thefirstcondition
A positive number is 5 times to another number.
→ First number = 5 × 2nd number
Consider the first number be 5xand 2nd number be x
According to thesecond condition
If 21 is added to both the numbers,then one of the new numbers becomes twice the another new number.
Given :-
A positive number is 5 times to another number. if 21 is added to both the numbers,then one of the new numbers becomes twice the another new number.
To Find :-
Two numbers
Solution :-
Let the number be x
Another number will be 5 × x = 5x
Now
[tex]\sf 5x+21=2(x+21)[/tex]
[tex]\sf 5x + 21=2x+42[/tex]
[tex]\sf 2x-5x = 21-42[/tex]
[tex]\sf -3x=-21[/tex]
[tex]\sf x = \dfrac{-21}{-3}[/tex]
[tex]\sf x = 7[/tex]
Hence,
First number = 7
Second number = 5 × 7 = 35
Given, A positive number is 5 times to another number. if 21 is added to both the numbers,then one of the new numbers becomes twice the another new number.
Solution :
According to the first condition
A positive number is 5 times to another number.
→ First number = 5 × 2nd number
According to the second condition
If 21 is added to both the numbers,then one of the new numbers becomes twice the another new number.
→ 5x + 21 = 2(x + 21)
→ 5x + 21 = 2x + 42
→ 5x – 2x = 42 – 21
→ 3x = 21
→ x = 21/3
→ x = 7
•°• First number = 5x = 5 × 7 = 35
•°• Second number = x = 7