A person has a chemical of Rs.50 per litre. Inwhat ratio should water be mixed in thatchemical, so that after selling the mixture atRs.40 per litre he may get a profit of 50%? About the author Adalyn
Step-by-step explanation: Let us assume that he sells just one liter of the solution cost of chemical = Rs. 50 selling price = Rs. 40 profit = 50% CP = SP (100/100+P%) = 40 (100/100+ 50) =( 40×100)/150 = 4000/150 = 26.67 For Rs. 50, he can buy 1 liter. So, For Rs. 26.67, he can buy (1×26.67 )/50 litre = (1000×26.67)/50= 533.4 ml Hence the amount of water required = 1000 – 533.4 = 466.6 ml Ratio = 533.4/466.6 = 2667/2333 Reply
Step-by-step explanation:
Let us assume that he sells just one liter of the solution
cost of chemical = Rs. 50
selling price = Rs. 40
profit = 50%
CP = SP (100/100+P%)
= 40 (100/100+ 50)
=( 40×100)/150 = 4000/150 = 26.67
For Rs. 50, he can buy 1 liter.
So, For Rs. 26.67, he can buy (1×26.67 )/50 litre
= (1000×26.67)/50= 533.4 ml
Hence the amount of water required = 1000 – 533.4
= 466.6 ml
Ratio = 533.4/466.6 = 2667/2333