A particle starts from rest with an acceleration 2m * s ^ – 2 . If the force producing acceleration is applied for 10 s then determine the velocity of the particle after 20 s.
(a) 40m * s ^ – 1
(c) 20m * s ^ – 1
(b) 10m * s ^ – 1
(d) 30m * s ^ – 1
[tex]\large\underline\bold\red{Given:-}[/tex]
• Initial velocity , u = 0m/s
• Acceleration , a = 2m/s²
• Time taken , t = 20 s
[tex]\large\underline\bold\red{To\:Find:-}[/tex]
• Final velocity , ( v )
[tex]\large\underline\bold\red{Solution:-}[/tex]
⠀⠀⠀⠀⠀⠀⠀⠀According to the Question
It is given that the particles start from rest & accelerate at 2m/s² . We have to calculate the final velocity of particles after 20s .
Using 1st equation of motion :–
ㅤㅤㅤㅤㅤㅤㅤv = u + at
where,
• v denote final velocity
• u denote initial velocity
• a denote acceleration
• t denote time taken
Substitute the value we get
[tex]:\implies[/tex] v = 0 + 2×20
[tex]:\implies[/tex] v = 0 + 40
[tex]:\implies[/tex] v = 40 m/s
Hence, the final velocity of the particles is 40m/s
So, the required option is (a) 40m/s .
[tex]\rule{300px}{.4ex}[/tex]
[tex]:\implies[/tex] v = 0 + 2×20
[tex]:\implies[/tex] v = 0 + 40
[tex]:\implies[/tex] v = 40 m/s
(a) 40m/s .