2 thoughts on “A moving train is brought to rest within 20 seconds by applying brakes. find the initial velocity, if the retardation due to brake”
Understanding the question: This question says that we have to find out the initial velocity if a moving train is brought to rest within 20 seconds by applying brakes. And the retardation due to brakes is [tex]{\sf{2 \: ms^{-2}}}[/tex] Let’s do it!
Given that:
Final velocity = [tex]{\sf{0 \: ms^{-1}}}[/tex]
Acceleration = [tex]{\sf{-2 \: ms^{-2}}}[/tex]
Time taken = 20 seconds
Don’t beconfused!
• Final velocity came as zero because moving train is brought to rest.
• Acceleration came in negative beacuse the train retards.
To calculate:
The initial velocity
Solution:
The initial velocity = 40 m/s
Using concept:
First law of motion
Usingformula:
v = u + at
Where, v denotes final velocity , u denotes initial velocity , a denotes acceleration and t denotes time.
Understanding the question: This question says that we have to find out the initial velocity if a moving train is brought to rest within 20 seconds by applying brakes. And the retardation due to brakes is [tex]{\sf{2 \: ms^{-2}}}[/tex] Let’s do it!
Given that:
Don’t be confused!
• Final velocity came as zero because moving train is brought to rest.
• Acceleration came in negative beacuse the train retards.
To calculate:
Solution:
Using concept:
Using formula:
Where, v denotes final velocity , u denotes initial velocity , a denotes acceleration and t denotes time.
Full Solution:
→ v = u + at
→ 0 = u + (-2)(20)
→ 0 = u + (-40)
→ 0 = u – 40
→ 0 + 40 = u
→ 40 = u
→ u = 40 m/s
→ Initial velocity = 40 m/s
Answer:
Please mark as brainliest...
Step-by-step explanation:
v = u + at
0 = u + (-2)(20)
0 = u + (-40)
0 = u – 40
0 + 40 = u
40 = u
u = 40 m/s
Initial velocity = 40 m/s