A metal wire 36cm long is bent to form a rectangle find its dimensions when its area is maximum About the author Samantha
Answer: Let the length and breadth of a rectangle be I and b. .. Perimeter of rectangle = 2 (1 + b) = 36cm .:. 1+b=18 Area of rectangle = 1x b = 1 (18-1) Let f(1) = 181-12 f(1) = 18-21 and f(1) = -2 Consider, f ‘(I) = 0 .. 18-21 0 .. 18 = 21 l= 9 For 1 = 9, f”(9) = -2 <0 .. f(x), i.e. area is maximum when I cm and b = 18-9 [form (i)] = 9 cm Reply
Answer:
Let the length and breadth of a rectangle be I and b.
.. Perimeter of rectangle = 2 (1 + b) =
36cm
.:. 1+b=18
Area of rectangle = 1x b = 1 (18-1)
Let f(1) = 181-12
f(1) = 18-21
and f(1) = -2
Consider, f ‘(I) = 0
.. 18-21 0
.. 18 = 21
l= 9
For 1 = 9,
f”(9) = -2 <0
.. f(x), i.e. area is maximum when I
cm
and b = 18-9 [form (i)]
= 9 cm