A man has Php 45,000 which he invests partly at a simple interest of 5% and the rest at 3 1/2 % per annum. The annual income from 3 1/2 % investment exceeds the income from the 5% investment by Php 65. Represent the amount of each investment. About the author Isabella
Answer: Let x be the amount he invests in 5% Then the amount he invests in 3 1/2 % is 45000-x (45000-x)(7/2)/100 -x(5)/100=65 (45000-x)×7-10x=65×200 315000-7x-10x=13000 17x=(315-13)×1000 x=302000/17 Other amount is ,45000-302000/17 Reply
Answer:
Let x be the amount he invests in 5%
Then the amount he invests in 3 1/2 % is 45000-x
(45000-x)(7/2)/100 -x(5)/100=65
(45000-x)×7-10x=65×200
315000-7x-10x=13000
17x=(315-13)×1000
x=302000/17
Other amount is ,45000-302000/17