1 thought on “A e Euclid’s division algorithm to find the HCF of:<br />135 and 225<br />”
Answer:
45
Step-by-step explanation:
135 = 90 × 1 + 45
225 = 135 × 1 + 90Again, 45 ≠ 0, repeating the above step for 45, we get,
90 = 45 × 2 + 0
The remainder is now zero, so our method stops here. Since, in the last step, the divisor is 45, therefore, HCF (225,135) = HCF (135, 90) = HCF (90, 45) = 45.
Answer:
45
Step-by-step explanation:
135 = 90 × 1 + 45
225 = 135 × 1 + 90Again, 45 ≠ 0, repeating the above step for 45, we get,
90 = 45 × 2 + 0
The remainder is now zero, so our method stops here. Since, in the last step, the divisor is 45, therefore, HCF (225,135) = HCF (135, 90) = HCF (90, 45) = 45.
Hence, the HCF of 225 and 135 is 45.
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