Contact Style About

A cuboidal box of dimensions 1 m × 2 m × 1.5 m is to be painted except its bottom. Calculate how much area of the box has to be pa

By Cora

A cuboidal box of dimensions 1 m × 2 m × 1.5 m is to be painted except its bottom. Calculate how much area of the box has to be painted.

Spam nhi krne ka wrna
10 answers reported badly​

About the author
Cora

the cost of 8 books is ₹1057.20what is the cost of 1 book.
solve the following word problem​

there were many guests at the wedding of cinderella and prince Charming They wore different-coloured clothes. Complete the table.<

2 thoughts on “A cuboidal box of dimensions 1 m × 2 m × 1.5 m is to be painted except its bottom. Calculate how much area of the box has to be pa”

  1. Area of the bottom of the cuboid = L × B

    　　　　　　　　　　　 = 1 × 2

    　　　　　　　　　　　 = 2 m²

    　　　　　　　　　　　

    As we know that, The surface area of a cuboid = 2(lb + lh + bh)

    　　　　　　　　　　　

    But here the bottom part is not to be painted.

    　　　　　　　　　　　

    Surface area of box to be painted = 2(lb + lh + bh)

    　　　　　 = 2 ( 1 × 2 + 2 × 1.5 + 1.5 × 1 )

    　　　　　 = 2 ( 2 + 3 + 1.5 )

    　　　　　 = 2 + 6.5

    　　　　　 = 13 m²

    　　　　　　　　　　　

    According to the question ( Bottom of the box isn’t painted ).

    　　　　　　　　　　　

    Area of the box painted = (13 -) m² = 11 m²

    　　　　　　

    Hence, the required surface area of the cuboidal box = 11 m2

    Reply

  2. ✧ Question :

    　　　　　　　　　　　

    • A cuboidal box of dimensions 1 m × 2 m × 1.5 m is to be painted except its bottom. Calculate how much area of the box has to be painted.

    　　　

    ✧ Given :

    　　　　　　　　　　　

    • Length of the box, l = 2 m
    • Breadth of box, b = 1 m
    • Height of box, h = 1.5 m

    　　　　　　　　　　　

    ✧ To Find :

    　　　　　　　　　　　

    • How much area of the box have to be painted

    　　　　　　　　　　　

    ✧ Solution :

    　　　　　　　　　　　

    Area of the bottom of the cuboid = L × B

    　　　　　　　　　　　 = 1 × 2

    　　　　　　　　　　　 = 2 m²

    　　　　　　　　　　　

    As we know that, The surface area of a cuboid = 2(lb + lh + bh)

    　　　　　　　　　　　

    But here the bottom part is not to be painted.

    　　　　　　　　　　　

    Surface area of box to be painted = 2(lb + lh + bh)

    　　　　　 = 2 ( 1 × 2 + 2 × 1.5 + 1.5 × 1 )

    　　　　　 = 2 ( 2 + 3 + 1.5 )

    　　　　　 = 2 + 6.5

    　　　　　 = 13 m²

    　　　　　　　　　　　

    According to the question ( Bottom of the box isn’t painted ).

    　　　　　　　　　　　

    Area of the box painted = (13 -) m² = 11 m²

    　　　　　　

    Hence, the required surface area of the cuboidal box = 11 m2

    [tex] [/tex]

    Reply

Leave a Comment