A country’s population 1994 was 52 million. In 2000 it was 55 million. Estimate the population in 2003 using the exponential growth formula. Round your answer to the nearest million About the author Mia
Answer: Popul@1994 = 52,000,000 P@2000 = 55,000,000 P@2003 = ? r = ? Equation: P = Po * e^(rt) —– Solve r: P/Po = e^(rt) ln(P/Po) = rt r = ln(P/Po)/t r = ln(P@2000/P@1994)/(2000-1994) r = ln(55M/52M)/6 r = 0.009348 —- Solve for P@2003 t = 2003 – 1994 = 9 P@2003 = P@1994 * e^(rt) P@2003 = 52M * e^(0.009348*9) P@2003 = 56,564,292.9 approximately 57M. Step-by-step explanation: PLEASE MARK AS BRAINLIEST Reply
Answer:
Popul@1994 = 52,000,000
P@2000 = 55,000,000
P@2003 = ?
r = ?
Equation: P = Po * e^(rt)
—–
Solve r:
P/Po = e^(rt)
ln(P/Po) = rt
r = ln(P/Po)/t
r = ln(P@2000/P@1994)/(2000-1994)
r = ln(55M/52M)/6
r = 0.009348
—-
Solve for P@2003
t = 2003 – 1994 = 9
P@2003 = P@1994 * e^(rt)
P@2003 = 52M * e^(0.009348*9)
P@2003 = 56,564,292.9
approximately 57M.
Step-by-step explanation:
PLEASE MARK AS BRAINLIEST