A conical heap of wheat of diameter 3.5 m is 12 m high. How much wheat is contained
by the heap.​

Answer:

80.54 m square

Step-by-step explanation:

It is given that

Diameter of the conical heap =9 m

Radius of the conical heap =

2

9

=4.5 m

Height of the conical heap =3.5 m

We know that

Volume of the conical heap =

3

1

πr

2

h

By substituting the values

Volume of the conical heap =

3

1

×3.14×4.5

2

×3.5

On further calculation

Volume of the conical heap =3.14×1.5×4.5×3.5

So we get

Volume of the conical heap =74.1825 m

3

We know that

Slant height l=

(r

2

+h

2

By substituting the values

l=

(4.5

2

+3.5

2

)

On further calculation

l=

32.5

So we get

l=5.7 m

We know that

Curved surface area of the conical heap =πrl

By substituting the values

Curved surface area of the conical heap =3.14×4.5×5.7

On further calculation

Curved surface area of the conical heap =80.54 m

2

Therefore, 80.54 m square

of canvas is required to cover the heap of wheat.