a conducting wire carries 10^21 electrons and in 4 minutes what is the charge flowing through the wire. a). 150C b). 300C c). 600C d). 500C. .. please answer it.. About the author Ximena
▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂ [tex] \: \: \: \: \: \: \: \underline{\boxed{ \frak{\pmb{ \: Given: – }}}} [/tex] Number of electrons = 10²¹ electrons Time taken (t)= 4 mins = 240 s [tex] \: \: \: \: \: \: \: \: \underline{\boxed{ \frak{\pmb{ \:To \: find:- \: }}}}[/tex] What is the charge flowing through the wire. ▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂ [tex] \: \: \: \: \: \: \: \: \underline{\boxed{ \frak{\pmb{ \:Solution:- \: }}}}[/tex] First we have to find the charge of the conductor. By quantization of charges we know that [tex] \: \: \: \: \: \: \: \: \underline{ \boxed{\sf\: q = n}}[/tex] ▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂ where e = charge of an electron = 1.6 × 10⁻¹⁹ C ◕ Substituting the datas we get :– q = 10²¹ × 1.6 × 10⁻¹⁹ q = 1.6 × 10² C ߷︎ The current flowing through a conductor is given by : [tex] \: \: \: \sf \: I = \dfrac{q}{t} [/tex] ◕ Next, Substituting the datas :– [tex] \: \: \: \red\longmapsto\sf \: I = 1.6 × \dfrac{10²}{240} [/tex] [tex] \: \: \: \: \red \longmapsto \underline{\boxed{\sf \: I = 0.67 ≈ 0.7 A}}[/tex] ▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂ ❍ Hence current flowing through the conductor is 0.7 A. [tex] \: \: \: \: ❍ \: \underline{\boxed{\rm{Current=0.7\:A}}}[/tex] ★ Therefore, option d is correct. Reply
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[tex] \: \: \: \: \: \: \: \underline{\boxed{ \frak{\pmb{ \: Given: – }}}} [/tex]
[tex] \: \: \: \: \: \: \: \: \underline{\boxed{ \frak{\pmb{ \:To \: find:- \: }}}}[/tex]
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[tex] \: \: \: \: \: \: \: \: \underline{\boxed{ \frak{\pmb{ \:Solution:- \: }}}}[/tex]
[tex] \: \: \: \: \: \: \: \: \underline{ \boxed{\sf\: q = n}}[/tex]
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where e = charge of an electron = 1.6 × 10⁻¹⁹ C
◕ Substituting the datas we get :–
q = 10²¹ × 1.6 × 10⁻¹⁹
q = 1.6 × 10² C
߷︎ The current flowing through a conductor is given by :
[tex] \: \: \: \sf \: I = \dfrac{q}{t} [/tex]
◕ Next, Substituting the datas :–
[tex] \: \: \: \red\longmapsto\sf \: I = 1.6 × \dfrac{10²}{240} [/tex]
[tex] \: \: \: \: \red \longmapsto \underline{\boxed{\sf \: I = 0.67 ≈ 0.7 A}}[/tex]
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❍ Hence current flowing through the conductor is 0.7 A.
[tex] \: \: \: \: ❍ \: \underline{\boxed{\rm{Current=0.7\:A}}}[/tex]
★ Therefore, option d is correct.