Contact Style About

A carpenter wants to manufacture a 3 metre ladder having rungs 25 cm apart. The rungs decreases uniformly in length from 45 cm at

By Amaya

A carpenter wants to manufacture a 3 metre ladder having rungs 25 cm apart. The rungs decreases uniformly in length from 45 cm at the bottom at 25 cm at the top and the top and bottom rungs are 2.5 metre apart.
Based on the above information answer the following questions :
(i) Total number of rungs in the ladder.
(ii) The lengths of rungs from bottom to top form an A.P. with first and last terms as 45 cm and 25 cm respectively. The common difference of the A.P. formed.
(iii) The length of the middle rung.
(iv) Length of the wood used for rungs.
(v) length of wood required for the ladder.

thoda bada ho gya ●︿●

koi solve kl do please ●︿●​

About the author
Amaya

Surface tension of a solution of a surface active substance with concentration 0.056 mole/l at 293k is equal to 4.33.10^-2N/M. Cal

pls answer me whats the coordinate of point E if u answer im going to giveaway $10,000

1 thought on “A carpenter wants to manufacture a 3 metre ladder having rungs 25 cm apart. The rungs decreases uniformly in length from 45 cm at”

  1. [tex]\small{\fcolorbox{red}{indigo}{\small{\fcolorbox{red}{violet}{\small{\fcolorbox{red}{pink} {\small{\fcolorbox{red}{red}{\small{\fcolorbox{red}{springgreen}{\small{\fcolorbox{red}{blue}{\small{\fcolorbox{red}{yellow} {\small{\fcolorbox{red}{azure} {\small{\fcolorbox{red}{blue}{\small{\fcolorbox{red}{orange}{\huge{\fcolorbox{red}{green}{\large{\fcolorbox{blue}{red}{{\fcolorbox{orange}{aqua}{ANSWER}}}}}}}}}}}}}}}}}}}}}}}}}}[/tex]

    Distance between the starting rung and the top most rung = 250 cm

    Number of rungs in 250 cm with spacing of 25 cm = 250/25 = 10

    Including the bottom most rung the total number of rungs on the ladder = 11

    The length of rungs is an Arithmetic progression/series.

    Sum of lengths of all 11 rungs = (1st term + last term)/2 * number of rungs

    = (45+25)/2 * 11 = 385 cm

    Step-by-step explanation:

    Solution :-

    It is given that the top and bottom rungs are 250 cm apart and the gaps between two consecutive rungs is 25 cm.

    Therefore,

    Number of rungs = (250/25 + 1) = 11

    The largest rung is 45 cm long and the smallest one is 25 cm long.

    It is given that the rungs are decreasing uniformly in length from 45 cm at the bottom to 25 cm at the top.

    So, the lengths of the rungs from an A.P. with a = 45 cm and l = length of 11th rung = 25 cm.

    Therefore,

    Length of the wood required to form 11 rungs

    = n/2 (a + l) cm

    = 11/2(45 + 25) cm

    = 11/2 × 70

    = 385 cm.

    Hence, the required length of the wood to form these rungs is 3.85 m

    [tex]\huge\boxed{{Thanks}}[/tex]

    ——————————————————————————

    ——————————————————————————HOPE IT WILL HELP YOU ❤️❤️❤️

    ——————————————————————————HOPE IT WILL HELP YOU ❤️❤️❤️——————————————————————————

    Reply

Leave a Comment