A car starting from rest attains a velocity of 60 km/h in 1 minute. Calculate : (I) its average velocity, acceleration. (ii) distance travelled during first 1 minute. (iii)acceleration
The average velocity is 8.33 m/s, the acceleration is 0.278 m/s² and the distance traveled in first 1 min is 999.6 m. Hence, The average velocity is 8.33 m/s, the acceleration is 0.278 m/s² and the distance traveled in first 1 min is 999.6 m
Step-by-step explanation:
For first lens
Image distance v = 2u = 2 × (-50) = -100 cm
For second lens
Now u = – 190 cm, f = – 8 cm, m2 = ?
Net magnification = m1 m2 = 0.08
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Answer:
The average velocity is 8.33 m/s, the acceleration is 0.278 m/s² and the distance traveled in first 1 min is 999.6 m. Hence, The average velocity is 8.33 m/s, the acceleration is 0.278 m/s² and the distance traveled in first 1 min is 999.6 m