A car is starting its motion from the rest condition with an acceleration of 3 m/s². Find the speed of the car after 10 sec in km/h and distance travelled during 10 sec. About the author Aaliyah
ans.:- Spead of car after 10 sec. v = u + at = 0 + 3× 10 = 30 m/sec. = 30× 3600/1000 km/hr. = 10.8 km/h distance travelled during 10 sec. s = ut + 1/2 at^2 = 0 × 10 + 1/2 × 3 × 10^2 = 1/2 × 300 = 150 m = 150 × 0.001 hr. = 0.150 hr. Reply
ans.:-
Spead of car after 10 sec.
v = u + at
= 0 + 3× 10
= 30 m/sec.
= 30× 3600/1000 km/hr.
= 10.8 km/h
distance travelled during 10 sec.
s = ut + 1/2 at^2
= 0 × 10 + 1/2 × 3 × 10^2
= 1/2 × 300
= 150 m
= 150 × 0.001 hr.
= 0.150 hr.