a car is moving with a velocity 12m/s and stops within 5s find its retardation. About the author Amelia
u=12m/s v=0m/s(final velocity is zero because it will be at rest after stopping t=5s a=v-u/t [tex]a = \frac{v – u}{t} [/tex] [tex]a = \frac{0 – 12}{5} [/tex] [tex]a = \frac{ – 12}{5} [/tex] [tex]a = – 2.5m[/tex] therefore retardation is -2.5m/s^2 Reply
u=12m/s
v=0m/s(final velocity is zero because it will be at rest after stopping
t=5s
a=v-u/t
[tex]a = \frac{v – u}{t} [/tex]
[tex]a = \frac{0 – 12}{5} [/tex]
[tex]a = \frac{ – 12}{5} [/tex]
[tex]a = – 2.5m[/tex]
therefore retardation is -2.5m/s^2
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