A car accelerates uniformly from 18 km/hr to 36 km/hr in 5 seconds. Calculate the acceleration. (a) 1 ms-2 (b) 3.6 ms-2 (c) 2 ms-2 (d) 2.6 ms-2 About the author Evelyn
Given, u=18km/h = 18 × 1000 ÷ 60 × 60 = 5m/s V=36km/hr = 36 × 1000 ÷ 60 × 60 = 10m/s t= 5 sec acceleration, a=? 1st equation of motion, v=u+at 10=5+5a 5a=5 a= 5 ÷ 5 = 1m/s therefore the correct option is 1ms-2 Reply
Answer: (a) 1 ms-2 Explanation: acceleration = (Final Speed – Initial Speed)/time Convert 36 km/hr to m/sec 36 km/hr x 1000m / 3600 sec = 10 m/sec 18 km/hr x 1000 / 3600 sec = 5 m/sec a = (10 m/sec – 5 m’sec)/5 sec a = 5m/sec / 5 sec a = 1 ms-2 Reply
Given,
u=18km/h = 18 × 1000 ÷ 60 × 60 = 5m/s
V=36km/hr = 36 × 1000 ÷ 60 × 60 = 10m/s
t= 5 sec
acceleration, a=?
1st equation of motion,
v=u+at
10=5+5a
5a=5
a= 5 ÷ 5 = 1m/s
therefore the correct option is 1ms-2
Answer:
(a) 1 ms-2
Explanation:
acceleration = (Final Speed – Initial Speed)/time
Convert 36 km/hr to m/sec
36 km/hr x 1000m / 3600 sec = 10 m/sec
18 km/hr x 1000 / 3600 sec = 5 m/sec
a = (10 m/sec – 5 m’sec)/5 sec
a = 5m/sec / 5 sec
a = 1 ms-2