A can finish a piece of work in 30 days. He
worked alone for 3 days and B joined him. To-
gether they could finish the

By Luna

A can finish a piece of work in 30 days. He
worked alone for 3 days and B joined him. To-
gether they could finish the remaining work in 9
days. In how many days B alone can finish the
same piece of work ?​

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Luna

2 thoughts on “A can finish a piece of work in 30 days. He<br />worked alone for 3 days and B joined him. To-<br />gether they could finish the”

  1. Answer:

    A can finish a piece of work in 30 days. He worked alone for 6 days and B joined him. Together they could finish the remaining work in 9 days. In how many days can B alone can finish the same piece of work?

    A- 30 days for full work; 1 day: 1/30 work.

    6 days: 6/30 work done; 6/30 is 1/5.

    Remaining work:4/5

    Together done in 9 days.

    Together in one day: (4/5)÷9=4/45=8/90

    Done by A in one day: 1/30=3/90

    Done by B in one day=(8/90)-(3/90)=(8–3)/90=5/90=1/18

    B does 1/18 work per day: so 18 days required to complete work alone.

    Ans: 18 days.

    Alternate method: 6, 9 and 30 are numbers used in problem description. So, let us take common multiple; 90 is one such number.

    We consider full work as 90 units.

    A does 90 units in 30 days.; so 3 units per day.

    In 6 days A does6×3=18 units.

    Remaining work =72 units done by A and B together in 9 days.; 8 units per day.

    Out of 8 units per day together, A does 3 units.

    So, B does 5 units per day.

    At 5 units per day, B needs 18 days to complete 90 units of work (full work).

    Ans: 18 days.

    Step-by-step explanation:

    itz Niharika here

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