A body moves along the curved path of quarter circle . Calculate the ratio of distance to displacement pls tell About the author Anna
Answer: [tex]\pi : 2\sqrt{2}[/tex] Explanation: Given, A body moves along a curved path of quarter circle. To Find :- Ratio of Distance to Displacement. Solution :- Distance covered by body moving along a curved path of quarter circle = Perimeter of the quarter circle :- Perimeter of the quarter circle = Perimeter of the circle/4 [tex]=\dfrac{2\pi r}{4}[/tex] [ r = radius] [tex]=\dfrac{\pi r}{2}[/tex] Displacement of the body moving along a curved path of quarter circle = Perimeter of the quarter circle :- In the case of a quadrant, the term displacement indicates the hypotenuse side :- [tex](hypotenuse\:side)^2=(opposite\:side)^2+(adjacent\:side)^2[/tex] [tex](hypotenuse\:side)^2=r^2+r^2[/tex] [tex](hypotenuse\:side)^2=2r^2[/tex] hypotenuse side = displacement = √2r. Ration of Distance to Displacement :- [tex]=\dfrac{\pi r}{2} : \sqrt{2}r[/tex] [tex]=\dfrac{\dfrac{\pi r}{2}}{\sqrt{2}r}[/tex] [tex]=\dfrac{\pi r}{2}\times \dfrac{1}{\sqrt{2}r}[/tex] [tex]=\pi : 2\sqrt{2}[/tex] Reply
Answer:
[tex]\pi : 2\sqrt{2}[/tex]
Explanation:
Given,
A body moves along a curved path of quarter circle.
To Find :-
Ratio of Distance to Displacement.
Solution :-
Distance covered by body moving along a curved path of quarter circle = Perimeter of the quarter circle :-
Perimeter of the quarter circle = Perimeter of the circle/4
[tex]=\dfrac{2\pi r}{4}[/tex]
[ r = radius]
[tex]=\dfrac{\pi r}{2}[/tex]
Displacement of the body moving along a curved path of quarter circle = Perimeter of the quarter circle :-
In the case of a quadrant, the term displacement indicates the hypotenuse side :-
[tex](hypotenuse\:side)^2=(opposite\:side)^2+(adjacent\:side)^2[/tex]
[tex](hypotenuse\:side)^2=r^2+r^2[/tex]
[tex](hypotenuse\:side)^2=2r^2[/tex]
hypotenuse side = displacement = √2r.
Ration of Distance to Displacement :-
[tex]=\dfrac{\pi r}{2} : \sqrt{2}r[/tex]
[tex]=\dfrac{\dfrac{\pi r}{2}}{\sqrt{2}r}[/tex]
[tex]=\dfrac{\pi r}{2}\times \dfrac{1}{\sqrt{2}r}[/tex]
[tex]=\pi : 2\sqrt{2}[/tex]