a 2digit no. is 3 more than 4times the sum of its digits.If 18 is added to the no. the digits are reversed. FIND THE NO.(number)?

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1. Answer:

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   Step-by-step explanation:

   so let the two digit number be 10x+y

   where digit at ones pace is y and that of tens is x

   according to first criterion,,

   10x+y=3+4(x+y)

   ie 10x+y=3+4x+4y

   ie 6x-3y=3

   so dividing by 3 on both sides,we get,

   2x-y=1

   hence y=2x-1 (1)

   according to second case

   10x+y+18=10y+x

   so 9x-9y=-18

   ie dividing by 9 on both sides we get

   x-y=-2

   so substitute value of y from (1)

   we get

   x-(2x-1)=-2

   ie x-2x+1=-2

   so -x=–3

   so x=3

   substitute value of x in any of two equations

   we get,,y=5

   so our assumed two digit number was 10x+y

   =(10×3)+5

   =30+5

   =35

   hence required two digit number is 35

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