Answer: Let the three consecutive multiples of 11 are 11x, 11x+11 and 11x+22 Their sum is 363 11x+11x+11+11x+22=363 33x+33=363 33x=363−33 33x=330 x= 33 330 x=10 First multiple =11x=11×10=110 Second multiple =11x+11=110+11=121 Third multiple =11x+22=110+22=132 FEEDBACK: MARK AS BRAINLIEST ANSWER Reply
Answer: Step-by-step explanation: LET THE CONSEQUTIVE MULTIPLES OF 11 BE X , X+11 , X+22 THEREFORE X+X+11+X+22=363 3X+33=363 3X=330 X=110 THE MULTIPLES ARE 110 , 121 , 132 (IT SHOULD BE 363 INSTEAD OF 343) Reply
Answer:
Let the three consecutive multiples of 11 are 11x, 11x+11 and 11x+22
Their sum is 363
11x+11x+11+11x+22=363
33x+33=363
33x=363−33
33x=330
x=
33
330
x=10
First multiple =11x=11×10=110
Second multiple =11x+11=110+11=121
Third multiple =11x+22=110+22=132
FEEDBACK:
MARK AS BRAINLIEST ANSWER
Answer:
Step-by-step explanation:
LET THE CONSEQUTIVE MULTIPLES OF 11 BE
X , X+11 , X+22
THEREFORE X+X+11+X+22=363
3X+33=363
3X=330
X=110
THE MULTIPLES ARE 110 , 121 , 132
(IT SHOULD BE 363 INSTEAD OF 343)