An object takes 4s to reach the ground from a height of 6m on a planet. What is the acceleration due to gravity on earth ?​

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1. [tex]\huge\purple{\underline{\underline{\mathfrak{\red{Answer:-}}}}}[/tex]

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   ✮ Given :-

   • Initial velocity (u) = 0m/s
   • Time taken (t) = 4s
   • Height (h) = 6m

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   ✥ Need To Find :-

   • Acceleration due to gravity (g)

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   ❂ Applied Formula :-

   [tex]\rm{h = ut + \dfrac{1}{2}\times gt^2}[/tex]

   • h = height
   • u = initial velocity
   • t = time

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   ❁ Solution :-

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   ⠀⠀⠀⠀➜ ⠀h = ut + ½ × gt²

   ⠀⠀⠀⠀➜⠀ 6 = 0 × 4 + ½ × g × 4²

   ⠀⠀⠀⠀➜⠀ 6 = 0 + ½ × g × 16

   ⠀⠀⠀⠀➜⠀ 6 = g × 8

   ⠀⠀⠀⠀➜⠀ 6 = 8g

   ⠀⠀⠀⠀➜⠀ 8g = 6

   ⠀⠀⠀⠀➜⠀ g = ¾

   ⠀⠀⠀⠀➜ ⠀g = 0.75m/s²

   ⠀

   ❆ Acceleration due to gravity is 0.75m/s²

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