1 thought on “If a and B are zeroes of the polynomial p(x) = 3x² – 10x + 7 , find the value of a² + b²”
Answer:
6.4
Step-by-step explanation:
Given : [tex]3x^{2} -10x+7[/tex]
Looking for : [tex]a^{2} +b^{2}[/tex] =?
Since the coeffienct is not 1, you would have to use a different method.
I used the slide, multiply and divide method.
Slide 3 to 7 and multiply to get 21: [tex]3x^{2} -10x+21[/tex]
Then factor normally: (x – 7)(x – 3)
Now use the divide portion of the method and divide 7 and 3 by 3, if you get a fraction that doesn’t simply, then move the 3 to the front: [tex](3x-7)(x-1)[/tex]
Solve for your zeros: a = [tex]\frac{7}{3}[/tex] & b = 1
Place them into the equation: [tex]\frac{7}{3} ^{2}+ 1^{2}[/tex] = [tex]\frac{58}{9}[/tex] = 6.4
Answer:
6.4
Step-by-step explanation:
Given : [tex]3x^{2} -10x+7[/tex]
Looking for : [tex]a^{2} +b^{2}[/tex] =?
Since the coeffienct is not 1, you would have to use a different method.
I used the slide, multiply and divide method.
Slide 3 to 7 and multiply to get 21: [tex]3x^{2} -10x+21[/tex]
Then factor normally: (x – 7)(x – 3)
Now use the divide portion of the method and divide 7 and 3 by 3, if you get a fraction that doesn’t simply, then move the 3 to the front: [tex](3x-7)(x-1)[/tex]
Solve for your zeros: a = [tex]\frac{7}{3}[/tex] & b = 1
Place them into the equation: [tex]\frac{7}{3} ^{2}+ 1^{2}[/tex] = [tex]\frac{58}{9}[/tex] = 6.4