Contact Style About

The ratio of the age of father and son in a family is 11: 6. If the age of the
mother is added to the age of the son then the

By Amaya

The ratio of the age of father and son in a family is 11: 6. If the age of the
mother is added to the age of the son then the ratio becomes 11: 16. If the
age of the son is 30 years, what is the age of the mother?
(a) 25 years (6) 50 years (c) 15 years (d) 45 years​

About the author
Amaya

4 8 40
9 4 ?
5 6 49 pleaze solution​

1. Can a polyhedron have for its faces
(i) 3 triangles?
(iii) a square and four triangles?​

2 thoughts on “The ratio of the age of father and son in a family is 11: 6. If the age of the<br />mother is added to the age of the son then the”

  2. [tex]\bf \underline{ \underline{\maltese\:Given} }[/tex]

    [tex] \sf The \: ratio \: of \: the \: age \: of \: father \: and \: son \: in \: a \: family \: is \: 11: 6[/tex]

    [tex] \sf If \: the \: age \: of \: the \: mother \: is \: added \: to \: the \: age \: of \: the \: son : [/tex]

    [tex] \sf \implies Then, the \: ratio \: becomes \: 11: 16[/tex]

    [tex] \sf Real \: age \: of \: son = 30 \: years. [/tex]

    [tex]\bf \underline{ \underline{\maltese\:To \: find } }[/tex]

    [tex] \sf \implies Age \: of \: mother = \: ? [/tex]

    [tex]\bf \underline{ \underline{\maltese\:Solution } }[/tex]

    [tex] \sf Let \: us \: assume \: that, [/tex]

    [tex] \sf \implies Age \: of \: father \: be \: 11x [/tex]

    [tex] \sf \implies Age \: of \: son \: be \: 6x [/tex]

    [tex] \sf \implies Age \: of \: mother \: be \: y [/tex]

    [tex] \bf \underline{ Now}, \sf according \: to \: question, [/tex]

    [tex] \sf \implies \bf \dfrac{11x}{6x + y} = \dfrac{11}{16} [/tex]

    [tex] \sf \implies 11(6x + y) = 16(11x)[/tex]

    [tex] \sf \implies 11(6x + y) = 176x[/tex]

    [tex] \sf \implies 66x +11y = 176x[/tex]

    [tex] \sf \implies 11y = 176x – 66x[/tex]

    [tex] \sf \implies 11y = 110x[/tex]

    [tex] \sf \implies y = \cancel \dfrac{110x}{11} [/tex]

    [tex] \sf \implies y = 10x[/tex]

    [tex] \bf \underline{ Now}, [/tex]

    [tex] \sf Since, age \: of \: son \: is \: 30 \: years. [/tex]

    [tex] \sf \implies 6x = 30 [/tex]

    [tex] \sf \implies x = \cancel \dfrac{30 }{6} [/tex]

    [tex] \sf \implies x = 5[/tex]

    [tex] \bf \underline{ Therefore}, [/tex]

    [tex] \sf \implies Age \: of \: mother \: (y) = \bf 10(x) = 10 \times5= 50 \: years[/tex]

    Reply

Leave a Comment