A number is fourth – fifth of others . If their sum is 180 . Find the numbers About the author Reagan
Answer: Numbers :– 100 & 80 . Step-by-step explanation: . Given – A number is fourth-fifth of others. If their sum is 180. Find the numbers. . Solution – If one of the is considered as x, so second will be ⅘of x . sum of both numbers = 180 [tex]x + \frac{4}{5} x = 180 \\ \\ = > \frac{(5 \times x) + 4x}{5} = 180 \\ \\ = > \frac{5x + 4x}{5} = 180 \\ \\ = > \frac{9x}{5} = 180 \\ \\ 9x = 180 \times 5 \\ \\ = > 9x = 900 \\ \\ = > x = 900 \div 9 \\ \\ = > x = 100[/tex] Hence one number is 100, second is ,⅘of x, so second :– [tex] \frac{4}{5} \times x \\ = > \frac{4}{5} \times 100 \\ = > \frac{400}{5} \\ = > 80[/tex] Hence second number is 80. . Sum of both number is 180 and a number is ⅘ of other, so our answer is correct. . hope it helps. Reply
Answer:
Numbers :–
100 & 80
.
Step-by-step explanation:
.
Given –
A number is fourth-fifth of others. If their sum is 180. Find the numbers.
.
Solution –
If one of the is considered as x, so second will be ⅘of x
.
sum of both numbers = 180
[tex]x + \frac{4}{5} x = 180 \\ \\ = > \frac{(5 \times x) + 4x}{5} = 180 \\ \\ = > \frac{5x + 4x}{5} = 180 \\ \\ = > \frac{9x}{5} = 180 \\ \\ 9x = 180 \times 5 \\ \\ = > 9x = 900 \\ \\ = > x = 900 \div 9 \\ \\ = > x = 100[/tex]
Hence one number is 100, second is ,⅘of x, so second :–
[tex] \frac{4}{5} \times x \\ = > \frac{4}{5} \times 100 \\ = > \frac{400}{5} \\ = > 80[/tex]
Hence second number is 80.
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Sum of both number is 180 and a number is ⅘ of other, so our answer is correct.
.
hope it helps.