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By Nevaeh

[tex] \large \mathbb \blue{ \fcolorbox{blue}{black}{ \: \:⫷ ⫷ \: \: Q : U :E : S : T : I : O : N \: \: ⫸⫸ \: }}[/tex]

A & B are sitting at a distance of 1 meter from each other. Masses of both are 80 kg and 75 kg , respectively .​ find Gravitational force between them. ​

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Nevaeh

Events which can never occur together In probability theories then it is classified as?

a.

mutually exhausti

Point Phas coordinates (-3,-4) and point Q has coordinates (3,5).
Calculate the shortest distance between P and Q.
Give

2 thoughts on “[tex] \large \mathbb \blue{ \fcolorbox{blue}{black}{ \: \:⫷ ⫷ \: \: Q : U :E : S : T : I : O : N \: \: ⫸⫸ \: }}[/tex]<b”

  1. GIVEN

    • Distance between A & B = 1m
    • Mass of A = 80 kg
    • Mass of B = 75 kg

    TO FIND

    • Gravitational Force between them.

    SOLUTION

    According to Newton’s Law,

    [tex] \large\boxed{\bf\blue{ f \: = \frac{Gm_1m_2}{ {r}^{2} }}} [/tex]

    [tex]\rm{F=\dfrac{6.67 \times {10}^{ – 11} \times 75 \times 80 }{ {1}^{2} } }[/tex]

    [tex]\rm{F=\dfrac{6.67 \times {10}^{ – 11} \times 75 \times 80 }{1} }[/tex]

    [tex]\rm{F=\dfrac{6.67 \times {10}^{ – 11} \times 6000 }{1} }[/tex]

    [tex]\rm{F=\dfrac{\cancel{6.67 \times {10}^{ – 11} \times 6000 }}{\bcancel{1}} }[/tex]

    [tex] \large \bold { \pmb{\boxed {\red{F = 4.002 \times {10}^{-7} \: \rm{Newton}}}}}[/tex]

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