3) Determine power rating of an electric motor if it
runs at 1440 r.p.m and line shaft transmits torque a
75 Nm. Assume

2 thoughts on “3) Determine power rating of an electric motor if it<br />runs at 1440 r.p.m and line shaft transmits torque a<br />75 Nm. Assume”

1. Answer:

   The tendency of force to rotate an object about an axis is called as torque or moment.

   Given: speed (n) : 1440 r.p.m, torque = 75 Nm, reduction ratio (I) = 1.6

   Formula: P = 2 p N T / 60

   Solution:

   i = n / N

   1.6 = 1440 / N

   N = 900 r.p.m

   P = (2 p N T)/ 60

   P = (2 x 3.14 x 900 x 75 ) /60

   P = 423900 /60

   = 7065 W

   = 7.065 kW

   Power rating of an electric motor is 7.065 kW

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2. The power rating of an electric motor is 7.068 kW

   Explanation:

   i = n / N

   1.6 = 1440 / N

   N = 900 r.p.m

   P = (2 π x 1440 x 75) / 60

   = 7068 W

   = 7.068 kW

   The power rating of an electric motor is 7.068 kW

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