. Two identical metallic cubes of side 5cm are melted to form a solid cylinder of radius 7cm. What will be the height of the cylinder so formed? (use π=22/7) About the author Ava
Answer: Given: Height (h) of cylindrical part = height (h) of the conical part =7 cm Diameter of the cylindrical part =12 cm Therefore, Radius (r) of the cylindrical part = 2 12 =6 cm So, Radius of the conical part =6 cm Slant height (l) of conical part = r 2 +h 2 cm = 6 2 +7 2 = 36+49 = 85 ≈9.22 cm. The total surface area of the remaining solid = CSA of the cylindrical part + CSA of the conical part + Base area of the circular part =2πrh+πrl+πr 2 =2× 7 22 ×6×7+ 7 22 ×6×9.22+ 7 22 ×6×6 =264+173.86+113.14 =551 cm 2 MARK ME AS BRAINLIST✌✌ PLEASE Reply
Answer:
Given:
Height (h) of cylindrical part = height (h) of the conical part =7 cm
Diameter of the cylindrical part =12 cm
Therefore, Radius (r) of the cylindrical part =
2
12
=6 cm
So, Radius of the conical part =6 cm
Slant height (l) of conical part =
r
2
+h
2
cm
=
6
2
+7
2
=
36+49
=
85
≈9.22 cm.
The total surface area of the remaining solid = CSA of the cylindrical part + CSA of the conical part + Base area of the circular part
=2πrh+πrl+πr
2
=2×
7
22
×6×7+
7
22
×6×9.22+
7
22
×6×6
=264+173.86+113.14
=551 cm
2
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