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Answer: ∠ROS=90 ∘ −∠POS−(i) ∠QOS=∠QOR+∠ROS=90 ∘ +∠ROS ⇒90 ∘ =∠QOS−∠ROS−(ii) Substituting (ii) in (i) we get ∠ROS=∠QOS−∠ROS−∠POS ⇒2∠ROS=∠QOS−∠POS ⇒∠ROS= 2 1 (∠QOS−∠POS) Hence proved. Step-by-step explanation: Mark me as Brainlist✌✌ please Reply
Answer:
∠ROS=90
∘
−∠POS−(i)
∠QOS=∠QOR+∠ROS=90
∘
+∠ROS
⇒90
∘
=∠QOS−∠ROS−(ii)
Substituting (ii) in (i) we get
∠ROS=∠QOS−∠ROS−∠POS
⇒2∠ROS=∠QOS−∠POS
⇒∠ROS=
2
1
(∠QOS−∠POS)
Hence proved.
Step-by-step explanation:
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