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[tex] \frac{9x – 7}{3x + 5} = \frac{3x – 4}{x + 6} [/tex]
please solve this
​​

By Alaia

[tex] \frac{9x – 7}{3x + 5} = \frac{3x – 4}{x + 6} [/tex]
please solve this
​​

About the author
Alaia


The length of a rectangle is 6 cm more than the side of a square, and the width of the
rectangle is 6 cm less than the

Without using trigonometric tables, prove that:
cos²57° – sin²33° = 1​

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