the hcf of the polynomial 10(a-1) (a-2)³,.120(a-3) (a-2)³ and 135(a+3) ( a-2)³ is About the author Kennedy
Answer: First expression = x2 – 3x – 18 = x2 – 6x + 3x – 18, by splitting the middle term – 3x = – 6x + 3x = x(x – 6) + 3(x – 6) = (x – 6) (x + 3) Second expression = x2 + 5x + 6 = x2 + 3x + 2x + 6, by splitting the middle term 5x = 3x + 2x = x(x + 3) + 2(x + 3) = (x + 3) (x + 2) mark me as Brainlist✌✌ please Reply
Answer:
First expression = x2 – 3x – 18
= x2 – 6x + 3x – 18, by splitting the middle term – 3x = – 6x + 3x
= x(x – 6) + 3(x – 6)
= (x – 6) (x + 3)
Second expression = x2 + 5x + 6
= x2 + 3x + 2x + 6, by splitting the middle term 5x = 3x + 2x
= x(x + 3) + 2(x + 3)
= (x + 3) (x + 2)
mark me as Brainlist✌✌ please
Answer:
a 3
Step-by-step explanation:
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