1. The displacement of a particle in SHM is given byy eqal to 5 sin pi t +pi /6Find its maximum acceleration and initial displacement About the author Genesis
Answer: x=5sinπt+12sin(πt+π/2) =5sinπt+12cosπt =13sin(πt+θ) where cosθ=5/12 Amplitude, A=max(x)=13 cm Time period, T=2π/ω=2π/π=2 s Initial phase, α=∠(x) t=0 =θα=cos −1 (5/12) Explanation: Hope this helps you buddy ✌️✌️ Reply
Answer:
x=5sinπt+12sin(πt+π/2)
=5sinπt+12cosπt
=13sin(πt+θ) where cosθ=5/12
Amplitude, A=max(x)=13 cm
Time period, T=2π/ω=2π/π=2 s
Initial phase, α=∠(x)
t=0 =θα=cos −1 (5/12)
Explanation:
Hope this helps you buddy ✌️✌️