3.If 87587A28 is a number divisible by 8,where A is a digit, how many suchnumbers are possible?(1) 5(3)3(2) 4(4)9 About the author Melody
Given: A number – 87587A28 which is divisible by 8. What To Find: We have to find – How many such numbers are possible to be divisible by 8 in the given options in place of A. How To Find: To find we have to – First, substitute each number given in the options in place of A. Next, use the divisibility rule of 8. Then, if the number is divisible we get an answer. Finally, we will get the possible number. Divisibility Rule Of 8: We take the 3 digits of the number and divide it by 8. There are two cases:- If the remainder is 0 then it is divisible by 8. If the remainder is not 0 then it is not divisible by 8. Solution: Number – 87587A28 A. 5 Let’s substitute it in the value of A. → A = 5 We will get – → 87587528 The three digits are – → 528 Divide it by 8, → 528 ÷ 8 The remainder is – → 0 ∴ Hence, 87587528 is divisible by 8. B. 3 Let’s substitute it in the value of A. → A = 3 We will get – → 87587328 The three digits are – → 328 Divide it by 8, → 328 ÷ 8 The remainder is – → 0 ∴ Hence, 87587328 is also divisible by 8. C. 4 Let’s substitute it in the value of A. → A = 4 We will get – → 87587428 The three digits are – → 428 Divide it by 8, → 428 ÷ 8 The remainder is – → 4 ∴ Hence, 87587428 is not divisible by 8. D. 9 Let’s substitute it in the value of A. → A = 3 We will get – → 87587928 The three digits are – → 928 Divide it by 8, → 928 ÷ 8 The remainder is – → 0 ∴ Hence, 87587928 is also divisible by 8. Final Answer: ∴ Thus, the numbers possible are – 87587528 — [5] 87587328 — [3] 87587928 — [9] Reply
Given:
A number –
What To Find:
We have to find –
How To Find:
To find we have to –
Divisibility Rule Of 8:
We take the 3 digits of the number and divide it by 8. There are two cases:-
Solution:
Number – 87587A28
A. 5
Let’s substitute it in the value of A.
→ A = 5
We will get –
→ 87587528
The three digits are –
→ 528
Divide it by 8,
→ 528 ÷ 8
The remainder is –
→ 0
∴ Hence, 87587528 is divisible by 8.
B. 3
Let’s substitute it in the value of A.
→ A = 3
We will get –
→ 87587328
The three digits are –
→ 328
Divide it by 8,
→ 328 ÷ 8
The remainder is –
→ 0
∴ Hence, 87587328 is also divisible by 8.
C. 4
Let’s substitute it in the value of A.
→ A = 4
We will get –
→ 87587428
The three digits are –
→ 428
Divide it by 8,
→ 428 ÷ 8
The remainder is –
→ 4
∴ Hence, 87587428 is not divisible by 8.
D. 9
Let’s substitute it in the value of A.
→ A = 3
We will get –
→ 87587928
The three digits are –
→ 928
Divide it by 8,
→ 928 ÷ 8
The remainder is –
→ 0
∴ Hence, 87587928 is also divisible by 8.
Final Answer:
∴ Thus, the numbers possible are –