What will be the length of the longest rod which can be put on the floor of a rectangle room measuring 12 m in length and 5 m breadth?Options13 m m14 mO 15 m12 m About the author Camila
Answer: The length of longest road which can be placed in a room of length 12m and 5m is 12m (option d) Reply
Given : • Dimensions of a rectangular room :- Length of the room = 12 m Breadth of the room = 5 m To find : • Length of the longest rod which can be put on the floor of the rectangular room Solution : ★ Formula to calculate the length of the longest rod which can be put on the floor = Diagonal of the floor :- [tex]\large{\boxed{\bf{\pink{Diagonal~ of ~rectangle = \sqrt{l^2 + b^2}}}}}[/tex] where, • l denotes the length • b denotes the breadth Substituting the given values :- [tex]\implies \sf Diagonal = \sqrt{(12)^2 + (5)^2}[/tex] [tex]\implies \sf Diagonal = \sqrt{144 + 25}[/tex] [tex]\implies \sf Diagonal = \sqrt{169}[/tex] [tex]\implies \sf Diagonal = \sqrt{13 \times 13}[/tex] [tex]\implies \sf Diagonal = \pm 13[/tex] As we know, the length of diagonal cannot be negative. So, the negative sign will get rejected. [tex]\implies \sf Diagonal = \pm 13 Reject ~ -ve[/tex] [tex]\implies \sf Diagonal = 13[/tex] Therefore, the length of the longest which can be put in a room measuring 12 m in length and 5 m breadth is 13 m Reply
Answer:
The length of longest road which can be placed in a room of length 12m and 5m is 12m (option d)
Given :
• Dimensions of a rectangular room :-
To find :
• Length of the longest rod which can be put on the floor of the rectangular room
Solution :
★ Formula to calculate the length of the longest rod which can be put on the floor = Diagonal of the floor :-
[tex]\large{\boxed{\bf{\pink{Diagonal~ of ~rectangle = \sqrt{l^2 + b^2}}}}}[/tex]
where,
• l denotes the length
• b denotes the breadth
Substituting the given values :-
[tex]\implies \sf Diagonal = \sqrt{(12)^2 + (5)^2}[/tex]
[tex]\implies \sf Diagonal = \sqrt{144 + 25}[/tex]
[tex]\implies \sf Diagonal = \sqrt{169}[/tex]
[tex]\implies \sf Diagonal = \sqrt{13 \times 13}[/tex]
[tex]\implies \sf Diagonal = \pm 13[/tex]
As we know, the length of diagonal cannot be negative. So, the negative sign will get rejected.
[tex]\implies \sf Diagonal = \pm 13 Reject ~ -ve[/tex]
[tex]\implies \sf Diagonal = 13[/tex]
Therefore, the length of the longest which can be put in a room measuring 12 m in length and 5 m breadth is 13 m