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15.8 g KMnO4 is completely treated with 0.2 M HCl solution According to reaction
2KMnO4 + 16HCI = 2KCl + 2MnCl2 + 5C12 + 8H20

By Samantha

15.8 g KMnO4 is completely treated with 0.2 M HCl solution According to reaction
2KMnO4 + 16HCI = 2KCl + 2MnCl2 + 5C12 + 8H20
Volume of HC1 in litre is-
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Samantha

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