When a number ismultiplied by 3, itsunit digit comes outto be 2. Which ofthese could beapossible result if thenumber is multipliedwith itself? About the author Adalynn
Step-by-step explanation: let the number be 10x+y, where 0<x,y<10. The condition says, [3*(10x+y)] -2 = 10y+x simplifying will give us the equation as 29x=7y+2 now max possible number for y is 9 and max possible value for R.H.S is 65. therefore to be in range with the R.H.S, the max possible value for x is 2. Thus, x can be either 1 or 2. If x=1, LHS=29 and no suitable value can be found for y. If x=2, LHS=58 and y can be 8 to satisfy the equation. Thus x=2 and y=8. So the number is 28. Verification: (28*3)-2=82 Reply
Step-by-step explanation:
let the number be 10x+y, where 0<x,y<10.
The condition says, [3*(10x+y)] -2 = 10y+x
simplifying will give us the equation as 29x=7y+2
now max possible number for y is 9 and max possible value for R.H.S is 65.
therefore to be in range with the R.H.S, the max possible value for x is 2.
Thus, x can be either 1 or 2. If x=1, LHS=29 and no suitable value can be found for y.
If x=2, LHS=58 and y can be 8 to satisfy the equation.
Thus x=2 and y=8.
So the number is 28.
Verification:
(28*3)-2=82