[tex] \large \mathbb \blue{ \fcolorbox{blue}{black}{ \: \:⫷ ⫷ \: \: Q : U :E : S : T : I : O : N \: \: ⫸⫸ \: }}[/tex]

August 3, 2021

By Serenity

2 thoughts on “[tex] \large \mathbb \blue{ \fcolorbox{blue}{black}{ \: \:⫷ ⫷ \: \: Q : U :E : S : T : I : O : N \: \: ⫸⫸ \: }}[/tex]<b”

1. GIVEN

   x² + 7x – 60

   Using quadratic formula

   [tex] \boxed{ \red { \pmb{x = \frac{ -b±√b²-4ac}{2a}}}}[/tex]

   Here, a = 1 , b = 7 & c = -60

   [tex] \bf \: \: x= \cfrac{ -7± \sqrt{7²-4(1)(-60)}}{2(1)}[/tex]

   [tex] \bf \: x= \cfrac{-7± \sqrt{49+240}}{2}[/tex]

   [tex] \bf \: x= \cfrac{ -7±√289}{2}[/tex]

   Discriminant, b²- 4ac is greater than zero,

   • That means there will be two real & distinct roots.

   [tex] \bf \: x= \cfrac{ -7±17}{2}[/tex]

   [tex] \large \boxed{ \bold{ \blue{x= 5 \: \: or \: -12}}}[/tex]

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2. x² −7x−60=0

   or, x²−12x+5x−60=0

   or, x(x−12)+5(x−12)=0

   or, (x−12)(x+5)=0

   or, x=12,−5.

   Reply