In a trapezium ABCD, AB || CD, the point P and the point Q lie on the side AB and BC respectively. PQ || AC, prove that area of triangle ADP = area of Triangle ACQ
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Answer:
Step-by-step explanation:
Prove that the diagonals of a parallelogram divide it into four triangles of … (i) area of ∆OAB + area of ∆OCD = area of || gm ABCD. … If E, F, G and H are mid-points of the sides AB, BC, CD and DA respectively of a … P, Q are any two points … (b) In the figure (2) given below, DE is drawn parallel to the diagonal AC of the.
Answer:
Step-by-step explanation:
Prove that the diagonals of a parallelogram divide it into four triangles of … (i) area of ∆OAB + area of ∆OCD = area of || gm ABCD. … If E, F, G and H are mid-points of the sides AB, BC, CD and DA respectively of a … P, Q are any two points … (b) In the figure (2) given below, DE is drawn parallel to the diagonal AC of the.