If A (3,0), B(-3,0) then the locus of the point P is such that PA^2+PB^2=18 is​

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If A (3,0), B(-3,0) then the locus of the point P is such that PA^2+PB^2=18 is​

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  1. Step-by-step explanation:

    let P(X, Y)

    If A (3,0), B(-3,0) then the locus of the point P is such that PA^2+PB^2=18 is

    [tex] ({x – 3})^{2} + {y}^{2} + {(x + 3)}^{2} + {y}^{2} = 18[/tex]

    [tex] {x}^{2} – 6x + 9 + {y}^{2} + {x}^{2} + 6x + 9 + {y}^{2} = 18[/tex]

    [tex]2 {x}^{2} + 2 {y}^{2} = 0[/tex]

    [tex] {x}^{2} + {y}^{2} = 0[/tex]

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