solve by formula method
[tex]3 {x}^{2} – 6x + 12 = 0[/tex]
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2 thoughts on “solve by formula method <br />[tex]3 {x}^{2} – 6x + 12 = 0[/tex]<br />​”

1. Step-by-step explanation:

   The equation 3x² – 6x + 12 = 0

   is of the form ax² + bx + c = 0,

   where,

   a = 3

   b = -6

   c = 12

   As per formula,

   \sf \quad \ \ x = \dfrac{- b ± \sqrt{b^2 – 4ac}}{2a} x=

   2a

   −b±

   b

   2

   −4ac

   \sf \Rightarrow x = \dfrac{-(-6) ± \sqrt{(-6)^2 – 4(3)(12) }}{2(3)}⇒x=

   2(3)

   −(−6)±

   (−6)

   2

   −4(3)(12)

   \sf \Rightarrow x = \dfrac{6 ± \sqrt{36(-3)}}{6}⇒x=

   6

   6±

   36(−3)

   \sf \Rightarrow x = \dfrac{6 ± 6 \sqrt{-3}}{6}⇒x=

   6

   6±6

   −3

   \sf \Rightarrow x = \dfrac{\cancel6( ± \sqrt{-3})}{\cancel6}⇒x=

   6

   6

   (±

   −3

   )

   \sf \Rightarrow x = 1 ± \sqrt{3 \times -1}⇒x=1±

   3×−1

   \sf{ \Rightarrow x = 1 ± \sqrt{3}}i⇒x=1±

   3

   i

   \begin{gathered} \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \rm Thank \ You!\end{gathered}

   Thank You!

   Reply

2. The equation 3x² – 6x + 12 = 0

   is of the form ax² + bx + c = 0,

   where,

   • a = 3
   • b = -6
   • c = 12

   As per formula,

   [tex] \sf \quad \ \ x = \dfrac{- b ± \sqrt{b^2 – 4ac}}{2a}[/tex]

   [tex] \sf \Rightarrow x = \dfrac{-(-6) ± \sqrt{(-6)^2 – 4(3)(12) }}{2(3)}[/tex]

   [tex] \sf \Rightarrow x = \dfrac{6 ± \sqrt{36(-3)}}{6}[/tex]

   [tex] \sf \Rightarrow x = \dfrac{6 ± 6 \sqrt{-3}}{6}[/tex]

   [tex] \sf \Rightarrow x = \dfrac{\cancel6( ± \sqrt{-3})}{\cancel6}[/tex]

   [tex] \sf \Rightarrow x = 1 ± \sqrt{3 \times -1}[/tex]

   [tex] \sf{ \Rightarrow x = 1 ± \sqrt{3}}i[/tex]

   [tex] \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \rm Thank \ You![/tex]

   Reply