a father is 3 times as older as his son . after 15 years , he will be twice as old as his son . find their present ages​

2 thoughts on “a father is 3 times as older as his son . after 15 years , he will be twice as old as his son . find their present ages​”

1. Let the age of son = x.

   Then the age of man will be 3 times as old as his son = 3x.

   After 15 years:

   Age of son = x + 15.

   Age of man = 3x + 15.

   Given that Man will be only twice as old as his son.

   3x + 15 = 2(x + 15)

   3x + 15 = 2x + 30

   3x = 2x + 15

   x = 15.

   Therefore the age of son = 15 years.

   the age of man = 45 years.

   Hope this helps!

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2. Answer:

   Here is your answer:

   Let the present age of son be X years

   then the present age of father be 3X years

   After 15 years

   Son’s age = (X + 15) years

   and father’s = (3X + 15)

   According to the question, we have

   => (3X + 13) = 2(X + 15)

   => 3X + 15 = 2X + 30

   => 3 X – 2 X = 30 – 15

   => X = 15

   .°. The present age of son = 15 years

   and present age of father = 3X = 15 × 3 = 45 years.

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