Answer: p(y)=y^2-y+1 So, p(0) = 0²-0+1 = 1 p(1) = 1²-1+1 = 1 p(2) = 2²-2+1 = 3 Please mark my answer as BRAINLIEST… Reply
Answer:
sorry buddy I need some points
Answer:
p(y)=y^2-y+1
So,
p(0) = 0²-0+1 = 1
p(1) = 1²-1+1 = 1
p(2) = 2²-2+1 = 3
Please mark my answer as BRAINLIEST…