The sum of three consecutive multiples of ‘5’ is 45. Which is the smallest of the three multiples. (i) 10 (ii) 15 (iii) 20 (iv) 25 About the author Samantha
Answer: Option A !! Let 5x be the smallest multiple of 5. Then, the three consecutive multiples shall be, ➝ 5x ➝5x+5 ➝5x+10 According to the question, ➝5x+5x+5+5x+10=45 ➝5x+5x+5x=45−15 ➝15x=30 ➝x=2 ∴ Smallest multiple =5x=5×2=10 Reply
Answer:
the smallest of the three as a consecutive multiple of 5 is (i) 10
Answer:
Option A !!
Let 5x be the smallest multiple of 5.
Then, the three consecutive multiples shall be,
➝ 5x
➝5x+5
➝5x+10
➝5x+5x+5+5x+10=45
➝5x+5x+5x=45−15
➝15x=30
➝x=2
∴ Smallest multiple =5x=5×2=10