the hypothnue of right triangle is 2 more than twice of one ofthe other side while the 3rd side is 13 more than half of the hypothnue find the length of all the side About the author Emery
Step-by-step explanation: Given :– The hypothnue of right triangle is 2 more than twice of one ofthe other side while the 3rd side is 13 more than half of the hypotenuse. To find :– Find the length of all the sides ? Solution :– Let the one side of the right angled triangle be X units Then the hypotenuse of the right angled triangle = 2 more than twice of the one side of the triangle = (2X+2) units The length of the third side = 13 more than half of the hypotenuse = (2X+2)/2 + 13 => 2(X+1)/2 + 13 => X+1+13 => (X+14) units The lengths are X units , (2X+2) units , (X+14) units We know that By Pythagoras theorem Hypotenuse^2 = 1st Side^2 + 2nd Side^2 => (2X+2)^2 = X^2+(X+14)^2 => (2X)^2+2(2X)(2)+2^2 = X^2+X^2+2(X)(14)+14^2 Since (a+b)^2 = a^2+2ab+b^2 => 4X^2+8X+4 = 2X^2+28X+196 => 4X^2+8X+4-2X^2-28X-196 = 0 => 2X^2-20X-192 = 0 => 2(X^2-10X-96) = 0 => X^2-10X-96 = 0/2 =>X^2-10X-96 = 0 => X^2+6X-16X-96 = 0 => X(X+6) -16(X+6) = 0 => (X+6)(X-16) = 0 =>X+6 = 0 or X-16 = 0 => X = -6 or X = 16 X cannot be negative X = 16 units One side = 16 units Hypotenuse = 2X+2 => 2(16)+2 => 32+2 => 34 units Third side = (34/2)+14 => 17+13 => 30 units The measurements are 16 units ,34 units , 30 units Answer:– The measurements of all the sides of the right angled triangle are 16 units , 34 units and 30 units Used formulae:– Pythagoras Theorem:– In a right angled triangle,the square of the hypotenuse is equal to the sum of the squares of the other sides. Reply
Step-by-step explanation:
Given :–
The hypothnue of right triangle is 2 more than twice of one ofthe other side while the 3rd side is 13 more than half of the hypotenuse.
To find :–
Find the length of all the sides ?
Solution :–
Let the one side of the right angled triangle be X units
Then the hypotenuse of the right angled triangle
= 2 more than twice of the one side of the triangle
= (2X+2) units
The length of the third side
= 13 more than half of the hypotenuse
= (2X+2)/2 + 13
=> 2(X+1)/2 + 13
=> X+1+13
=> (X+14) units
The lengths are X units , (2X+2) units , (X+14) units
We know that
By Pythagoras theorem
Hypotenuse^2 = 1st Side^2 + 2nd Side^2
=> (2X+2)^2 = X^2+(X+14)^2
=> (2X)^2+2(2X)(2)+2^2 = X^2+X^2+2(X)(14)+14^2
Since (a+b)^2 = a^2+2ab+b^2
=> 4X^2+8X+4 = 2X^2+28X+196
=> 4X^2+8X+4-2X^2-28X-196 = 0
=> 2X^2-20X-192 = 0
=> 2(X^2-10X-96) = 0
=> X^2-10X-96 = 0/2
=>X^2-10X-96 = 0
=> X^2+6X-16X-96 = 0
=> X(X+6) -16(X+6) = 0
=> (X+6)(X-16) = 0
=>X+6 = 0 or X-16 = 0
=> X = -6 or X = 16
X cannot be negative
X = 16 units
One side = 16 units
Hypotenuse = 2X+2
=> 2(16)+2
=> 32+2
=> 34 units
Third side = (34/2)+14
=> 17+13
=> 30 units
The measurements are 16 units ,34 units ,
30 units
Answer:–
The measurements of all the sides of the right angled triangle are 16 units , 34 units and
30 units
Used formulae:–
Pythagoras Theorem:–
In a right angled triangle,the square of the hypotenuse is equal to the sum of the squares of the other sides.