13. A bullet of mass 20 g moving with a velocity of
20 m s’ is brought to rest by a wooden plank.
Calculate the work don

2 thoughts on “13. A bullet of mass 20 g moving with a velocity of<br />20 m s’ is brought to rest by a wooden plank.<br />Calculate the work don”

1. Answer:

   mass, m = 20g (0.02kg)

   initial velocity, u = 75m/s

   final velocity = 0m/s

   distance, s = 5cm or 0.05m

   Using, v

   2

   = u

   2

   + 2as

   0 = 75

   2

   + 2a(0.05)

   a = 562.5m/s

   2

   $$ Force = mass \times acceleration $$

   $$ = 0.02 \times 562.5 $$

   = 11.25N

   Explanation:

   as you can put 20 ms removing 75 ms

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2. [tex]\small\underline\purple{Given:-}[/tex]

   mass, m = 20g (0.02kg)

   initial velocity, u = 75m/s

   final velocity = 0m/s

   distance, s = 5cm or 0.05m

   [tex]\small\underline\purple{Using Formula:-}[/tex]

   [tex] {v}^{2} + {u}^{2} = 2as[/tex]

   [tex]0 = {75}^{2} + 2a(0.5)[/tex]

   [tex]a = 562.5 \frac{m}{s} ^{2} [/tex]

   [tex]\small\underline\purple{Now:-}[/tex]

   Force = mass \times acceleration

   = 0.02 \times 562.5

   = 11.25N

   [tex]\sf\small\underline\purple{Note:-}[/tex]

   The mass and distance must be converted in to SI unit of system. Then you would get answer in newtons.

   Reply