One litre of N/2 HCl solution is heated in a beaker. It was observed that when the volume of the solution was reduced to 600 mL, 3.25 g of HCl in lost, calculate the normality of the new solution. in% About the author Piper
Answer: 0.685 Explanation: The original of 0.5N HCl solution of 1 litre had 18.225 gm of HCl Initially 18.225gm of HCl was dissolved in 1 liter of solution After heating , mass of HCl dissolved in the reduced 600mL of solution was found to be (18.225−3.25)gm=14.975 gm Hence Normality of new solution= Volume of solution in litre Equivalent weight of HCl mass N= 1000mL per litre 600mL Equivalent weight of HCl 14.497 N= 0.6 litre 36.45 14.497 N= 0.6 litre 0.3977 Meq N=0.685 Reply
Answer:
0.685
Explanation:
The original of 0.5N HCl solution of 1 litre had 18.225 gm of HCl
Initially 18.225gm of HCl was dissolved in 1 liter of solution
After heating , mass of HCl dissolved in the reduced 600mL of solution was found to be (18.225−3.25)gm=14.975 gm
Hence
Normality of new solution=
Volume of solution in litre
Equivalent weight of HCl mass
N=
1000mL per litre
600mL
Equivalent weight of HCl
14.497
N=
0.6 litre
36.45
14.497
N=
0.6 litre
0.3977 Meq
N=0.685