1) Base of a triangle is 9 and height is 5. Base of another triangle is 10 and height is 6. Find the ratio ofareas of these triangles. About the author Adeline
Answer: [tex]area \: of \: triangle \: 1 = \frac{1}{2} \times 9 \times 5 \\ = 22.5 \\ area \: of \: triangle \: 2 = \frac{1}{2} \times 10 \times 6 \\ = 30 \\ ratio \: of \: triangle \: 1 \: to \: triangle \: 2 \\ = 22.5:30 \\ = 11.25:15 \\ = 0.75:1[/tex] Step-by-step explanation: Plz mark my answer as brainliest plz thank also and don’t forget to follow so that you get your answers in very less time. Reply
Step-by-step explanation: 1st triangle base=9 height=5 Area of triangle =1/2×b×h =1/2×9×5 =45/2 or 22.5 2nd triangle base =10 height=6 area of triangle =1/2×b×h =1/2×10×6 =30 Ratio of 1st and 2nd triangle is 22.5:30 Reply
Answer:
[tex]area \: of \: triangle \: 1 = \frac{1}{2} \times 9 \times 5 \\ = 22.5 \\ area \: of \: triangle \: 2 = \frac{1}{2} \times 10 \times 6 \\ = 30 \\ ratio \: of \: triangle \: 1 \: to \: triangle \: 2 \\ = 22.5:30 \\ = 11.25:15 \\ = 0.75:1[/tex]
Step-by-step explanation:
Plz mark my answer as brainliest plz thank also and don’t forget to follow so that you get your answers in very less time.
Step-by-step explanation:
1st triangle
base=9
height=5
Area of triangle =1/2×b×h
=1/2×9×5
=45/2 or 22.5
2nd triangle
base =10
height=6
area of triangle =1/2×b×h
=1/2×10×6
=30
Ratio of 1st and 2nd triangle is 22.5:30