A particel moves 3m North, then 4m east, and then 12m vertically upwards, its displacement is 2​

1 thought on “A particel moves 3m North, then 4m east, and then 12m vertically upwards, its displacement is 2​”

1. Answer:

   Displacement=

   √(( x2^2 – x1^2) +( y2^2 – y1^2) + (z2^2 – z1^2))

   =√(( 3^2 – 0^2) +( 4^2 – 0^2) + (12^2 – 0^2))

   =√169

   =13

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