The number of moles of oxalic acid present in 400 ml of 0.025M of oxalic acid solution About the author Melody
Correct option is C 1.575 g n. factor for H2C2O4 =2 Equivalent weight =2M Normality = equivalentweight×volume(inmL)weight×1000 0.1=(2126)×250weight×1000 Therefore, weight = 1.575g Reply
Answer:
hello disha
how do u do
where so u live
Correct option is
C
1.575 g
n. factor for H2C2O4 =2
Equivalent weight =2M
Normality = equivalentweight×volume(inmL)weight×1000
0.1=(2126)×250weight×1000
Therefore, weight = 1.575g