Answer:– Consider, a+b+c ––––––––––––––––––––––– a-¹ b-¹ + b-¹ c-¹ + c-¹ a-¹ = a+b+c ––––––––––––––––––––––––––––– 1/ab+ a/abc + b/cab [ multiply and divide each terms in the denominator by the missing terms. i.e., c,a,b respectively ] a+b+c = ––––––––––––––––––– c+a+b ––––––––––––––––––– abc = 1/1/abc =abc hence proved ........ Reply
Answer:–
Consider,
a+b+c
–––––––––––––––––––––––
a-¹ b-¹ + b-¹ c-¹ + c-¹ a-¹
= a+b+c
–––––––––––––––––––––––––––––
1/ab+ a/abc + b/cab
[ multiply and divide each terms in the denominator by the missing terms. i.e., c,a,b respectively ]
a+b+c
= –––––––––––––––––––
c+a+b
–––––––––––––––––––
abc
= 1/1/abc
=abc
hence proved ........